substract 2D size of 2D triangle from 3D size of 3D triangle

Saegon Grade:
(√((a[x]-b[x])²+(a[y]-b[y])²+(a[z]-b[z])²))-(√((a[x]-b[x])²+(a[y]-b[y])²))

Loose reduction
Sg=√(a²x²-2abx²+b²x²+a²y²-2aby²+b²y²+a²z²-2abz²+b²z²)
Sg=√(ax-2a(bx²)+ay-2a(by²)+az-2a(bz²))²
Sg=ax-2ax²b+ay-2aby²+az-2abz²
Sg=a(x-2x²b+y-2by²+z-2bz²)
Sg=ax-2ax²b+ay²aby²+az²abz²
Sg=ax-2ax²b+a²by^4+a²bz^4
Sg=a(x-2x²b+aby^4+abz^4)
Sg=ax-2ax²b+a²by^4+a²bz^4
Sg=a(x-2x²b+(aby+abz^4)^8)
Sg=ax-2ax²b+a(aby+abz^4)^8
Sg=ax-2ax^2b+a(aby+abz^4)^8
Sg=(ax-2ax*ba(aby+abz))*16
Sg=(-2ax+ab^2(ax)(2ab(yz)))*16
Sg=-2^2*2+ax^2+ab(yz)*16
Sg=ô+ax²+ab*yz*16
Sg=ô+ax²+abyz16
Sg=ô+a2x+abyz16

Substitution
where ô=-2^2*2+2
where ¤ = bayz
where -¼ = -1^4 (inverse negative exponent)
where ¶ = ax
where î = xa

Saegon Formula:
Sg=ô¶+¤-¼
 or
Sg=ôî+¤-¼